Answer:
He scored 8 baskets worth 3 points and 4 baskets worth 2 points.
Step-by-step explanation:
Let Juarez scored x baskets worth 3 points and y baskets worth 2 points.
Thus, we have below equations.
\(3x+2y=32....(1)\)
And the second equation is
\(x=2y\)
From equation (1)
\(3(2y)+2y=32\\\\6y+2y\\32\\8y=32\\y=4\)
Plugging this value in (1)
\(3x+2(4)=32\\3x=32-8\\3x=24\\x=8\)
Hence, he scored 8 baskets worth 3 points and 4 baskets worth 2 points.
