A skyscraper casts a shadow 200 feet long. If the angle of elevation of the sun is 49 , then the height of the skyscraper is _____.
Answer:
Height of the skyscraper = 230.07 feet
Step-by-step explanation:
In the given triangle AB is a skyscraper that casts a shadow of 200 feet long.
If the angle of elevation of the sun is 49°
In the given right angle triangle ABC
tanC = \(\frac{AB}{BC}\)
\(tan49=\frac{AB}{200}\)
AB = 1.1504×200
= 230.07 feet
Therefore, the height of the skyscraper is 230.07 feet