To draw the lewis structure of the ion Ch3Ch2NH3+ given, we must know the number of bonds each element in the compound. C can have four bonds, H can only have 1 bond and N can have 5 bonds. In this case, first C has 3 H bonds and 1 C bond.The second C is bonded to the other C, 2 H's, and 1 N. N capable of 5 bonds is bonded to one C and 3 H's. The lacking one bond is reflected on the positive charge of the compound.
