Verified Answer :

meerkat18

I saw the diagram.

m∠BXA = 30° 20'
m∠CXB = 40° 35'

m∠CXA = ?

m∠CXA = m∠BXA + m∠CXB
m∠CXA = 30° 20' + 40° 35'
m∠CXA = 70° 55'

calculista

the picture in the attached figure

we know that

m∠BXA = \(30\)° \(20\)'
m∠CXB = \(40\)° \(35\)'

m∠CXA = ?

m∠CXA = m∠BXA + m∠CXB
m∠CXA = \(30\)° \(20\)' + \(40\)° \(35\)'
m∠CXA = \(70\)° \(55\)'

therefore

the answer is
m∠CXA = \(70\)° \(55\)'

View image calculista

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