Answer:
b) \(v = 110 km/h\) Towards South
Explanation:
First plane moves with uniform velocity of 125 km/h towards South
so time taken by the plane to move 350 km is given as
\(t_1 = \frac{350}{125}\)
\(t_1 = 2.8 hours\)
Now it has a layover time of 30 min
then it moves with uniform velocity of 115 km/h towards South
so time taken by the plane to move 220 km is given as
\(t_2 = \frac{220}{115}\)
\(t_2 = 1.9 hours\)
Now we have total displacement of the plane is
\(d = 220 + 350\)
\(d = 570 km\)
total time of the journey is given as
\(T = 2.8 + 0.5 + 1.9\)
\(T = 5.21 h\)
now average velocity is given as
\(v = \frac{d}{T}\)
\(v = \frac{570}{5.21}\)
\(v = 110 km/h\) Towards South
