Given the equation Square root of 2x plus 1 = 3, solve for x and identify if it is an extraneous solution.
To answer the question above, raise both sides of the equation to the power of two.
(sqrt (2x + 1))² = 3²
This will simplify into,
2x + 1 = 9
Solving for the value of x gives an answer of x = 4. This value is not an extraneous root as it satisfy the original equation even if it is inside the radical sign.
The value of x for the given equation is ±2.
An extraneous solution is a solution, such as that to an equation, that emerges from the process of solving the problem but is not a valid solution to the problem.
Here, given equation is
\(\sqrt{2x^2+1}\) = 3
On squaring both sides, we get
2x²+1 = 3²
2x² + 1 = 9
2x² = 8
x² = 4
x = ±2
Thus, the value of x for the given equation is ±2.
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