The solutions to a quadratic equation are x = 2 and x = 7. If k is a nonzero constant, which of the following must be equal to the quadratic equation?. a. k(x-2)(x-7)=0. b. (x-2)(x-7)+k=0. c. (x+2)(x+7)+k=0. d. k(x+2)(x+7)=0
ANSWER
The correct option is,
\(k(x - 2)(x - 7) = 0\)
EXPLANATION
We were given that the solutions of the quadratic equation are
\(x = 2\)
and
\(x = 7.\)
This tells us that,
\(x - 2\)
and
\(x - 7\)
are factors of the quadratic equation.
This implies that the quadratic equation is of the form,
\((x - 2)(x - 7) = 0\)
We were also told that
\(k\)
is a non zero constant.
This means that we can use k to multiply the whole equation and the solution will not be affected.
Our equation now becomes,
\(k(x - 2)(x - 7) = 0\)
Hence the correct answer is A.