An experiment using 35 guinea pigs is set up to study the weight of the pigs after injecting them with a drug. If the population mean is 23.5 grams with a standard deviation of 3.4 grams, what is the margin of error of the sample mean?
If the population mean
is 23.5 grams with a standard deviation of
3.4 grams, then the margin of error of the sample mean is 0.097 grams. The correct answer between all the
choices given is the first choice or letter A. I am hoping that this answer has
satisfied your query about this specific question.
The margin of error of the sample mean is approximate 0.255 gm.
The standard deviation is a measure of the amount of variation or dispersion of a set of values.
Here, Standard deviation = 3.4 gm
population mean = 23.5 gm
number of pigs = 35
Margin of Error = \(\frac{\sqrt{mean X SD} }{N}\)
=\(\frac{\sqrt{23.5 X 3.4} }{35}\)
= 0.255 gm
Thus, the margin of error of the sample mean is approximate 0.255 gm.
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