In a city, 49% of the adults are male. 24% of the adults are male and rent action-movie DVDs, and 10% of the adults are female and rent action-movie DVDs. If an adult is randomly selected for a survey, what is the probability that the adult rents action-movie DVDs, given that the adult is female?

I getting the probability of the adult female that will rent the action movies in DVDs in by dividing the possible probability outcome which is 10% of all adults by the total number of possible outcome. So all of the population of the female is 51% and the ones who rent is only 10%. the probability is 19%

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wifilethbridge wifilethbridge · Answer 2 · 2019-02-15T05:05:28-05:00

Answer:

0.19

Step-by-step explanation:

Since we are given that in a city there are 49 % = 0.49 adults

So, the females in the city = 100%-49% =51% = 0.51

24% of the adults are male and rent action-movie DVDs,

10% of the adults are female and rent action-movie DVDs.

Probability of occurring an event :

\(\frac{\text{favorable outcomes}}{\text{total outcomes}}\)

Now to find the probability that the adult rents action-movie DVDs, given that the adult is female:

Favorable outcomes(females rented action movie DVDs) = 10% =0.1

Total Outcomes (total females) =51%=0.51

So, probability that the adult rents action-movie DVDs, given that the adult is female:

\(\frac{\text{females rent movies}}{\text{total females}}\)

\(\frac{0.1}{0.51}\)

\(0.19\)

Thus the probability that the adult rents action-movie DVDs, given that the adult is female is 0.19