Verified Answer :

The percent data between 6.0 and 6.9 would
be 13.59%. Here’s the complete solution for this specific problem.

z = (X - Mean)/SD 
z1 = (6 - 5.1)/09 = + 1 
z2 = (6.9 - 5.1)/09 = + 2 
Required Percent = P(6 < X < 6.9)100 
= P(1 < z < 2)100 
= [P(z < 2) - P(z < 1)]100 
= [0.9772 - 0.8413]100 
= 0.1359*100 
= 13.59%


I am hoping that this has answered your query.

ashishdwivedilVT

The percent data between 6.0 and 6.9 would be 13.59%.

What is Standard Deviation?

The standard deviation is a measure of the amount of variation or dispersion of a set of values.

Here’s the given data are as follows,

z = (X - Mean)/SD

z₁ = (6 - 5.1)/09 = + 1

z₂ = (6.9 - 5.1)/09 = + 2

Required Percent = P(6 < X < 6.9) X 100

                              = P(1 < z < 2) X 100

                              = [P(z < 2) - P(z < 1)] X 100

                              = [0.9772 - 0.8413] X 100

                              = 0.1359 X 100

                              = 13.59%

Thus, the percent data between 6.0 and 6.9 would be 13.59%.

Learn more about Standard deviation from:

https://brainly.com/question/14747159

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