Find the 30th term of the following sequence. 1, 7, 13, 19,.. 174. 175. 180. 181.
The first term a = 1,
Common difference, d: 7 - 1 = 6.
a(n) = a + (n -1)d,
For 30th term. = 1 + (30 -1)6
= 1 + 296 = 1 + 174 = 175
The 30th term of the given sequence is 175
Arithmetic sequence is a sequence in which the differences between every consecutive terms are always same.
Example : 3, 5, 7, 9, ..... is an arithmetic sequence where the common difference is 2.
Formula of arithmetic sequence is , \(a_{n}\) = \(a_{1}\) + (n-1)d
where \(a_{n}\) = term in the sequence,
\(a_{1}\) = \(1^{st\\}\) term in the sequence,
d = common difference between terms
Given sequence is, 1, 7, 13, 19, ....
Common difference (d) = 7-1=13-7=6
\(1^{st\\}\) term in the sequence (\(a_{1}\)) = 1
∴ \(a_{30}\) = \(a_{1}\) + (n-1)d
= 1+(30-1)×6
= 1+29×6
= 1+174
= 175
∴ 30th term is 175.
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