calculate the amount of energy (in kJ) to convert 337 grams of liquid water from 0 degrees celsius to water vapor at 177 degrees celsius.
Answer:
The mount of heat required is 249.690 kJ.
Explanation:
Mass of the water,m =337 g
Specific heat capacity of the water,c = 4.186 J/g °C
Change in temperature =\(\Delta T=177^oC-0^oC=177^oC\)
Q = Heat required
\(Q=mc\Delta T=337 g\times 4.186 J/g ^oC\times 177^oC=249,690.7 J=249.690 kJ\)
1 kilo Joule = 1000 joules
The mount of heat required is 249.690 kJ.