3x+5>_7 please help me with this
3x + 5 \(\geq\) 7Subtract 5 to both sides so3x + 5 - 5 \(\geq\) 7 - 53x \(\geq\) 2Divide 3 to both sides3x \(\geq\) 2\(\frac{3x}{3} \geq \frac{2}{3}\)Cancel out the 3 on the left side,\(\frac{2}{3} = \frac{3}{2}\)\(x \geq 4\)
3x+5>_7Subtract 5 on both sides3x+5>_7 -5 -53x>_2Divide 3 on both sides to solve for xYou get:x>_2/3
