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Triangle XYZ is shown on the coordinate plane below:


Triangle XYZ on the coordinate plane with ordered pairs at X 4, 5, at Y 5, 3, at Z 1, 3


If triangle XYZ is reflected across the line y = 1 to create triangle X'Y'Z', what is the ordered pair of X'?

Verified Answer :

The new ordered pair would be
X= -4,5

Answer:

The ordered pair of X' are 4, -3.

Step-by-step explanation:

Since, the rule of reflection across a line y = p is,

\((x,y)\rightarrow (x,2p-y)\)

Here, the triangle XYZ is reflected across the line y = 1 and create the triangle X'Y'Z',

That is, p = 1,

Thus, the rule of reflection would be,

\((x,y)\rightarrow (x, 2-y)\)

Also, the coordinates of X are (4,5),

So, after reflection,

\((4,5)\rightarrow (4, 2-5)\)

Hence, the coordinates of X' are (4, -3).

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