Answer:
Given the equation:
\(y =x^2+2x+7\) and \(y=x+7\)
Equate these two equation we get;
\(x^2+2x+7 = x+7\)
Subtract 7 from both sides we get;
\(x^2+2x= x\)
Subtract x from both sides we get;
\(x^2+x= 0\)
or
\(x(x+1)=0\)
⇒x = 0 and x +1=0
⇒x = 0 and x = -1
Now, find the values of y:
For x = 0
y=x+7
y = 0+7 = 7
⇒(0, 7)
For x = -1
y=x+7
y = -1+7 =6
⇒(-1, 6)
Therefore, the solution set for the given equations are: (0, 7) and (-1, 6)
