how many moles of boron make up 1.20 × 1024 atoms of boron?
An Avogadro number of atoms of Boron make up 1 mole of Boron atom.
6.02 10²³ atoms make up 1 mole of Boron atom.
1.20 10²⁴ atoms will: (1.20 10²⁴ 1 ) / (6.02 * 10²³)
≈1.993 Mole of Boron atom.
Answer: 2 moles
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number \(6.023\times 10^{23}\) of particles.
Standard condition of temperature (STP) is 273 K and atmospheric pressure is 1 atm respectively.
To calculate the moles, we use the equation:
\(\text{Number of moles}=\frac{\text{Given atoms}}{\text {Avogadro's number}}=\frac{1.20\times 10^{24}}{6.023\times 10^{23}}=2moles\)
Thus 2 moles of boron make up \(1.20\times 10^{24}\) atoms of boron.