Dylan's dog weighs 12 times as much as his pet rabbit. The dog and rabbit weigh 104 pounds altogether. How much does Dylan's dog weigh?
\(*\\x-\ weight\ of\ dog\\\\ \frac{x}{12}-\ weight\ of\ per\ rabbit\\\\ x+\frac{x}{12}=104\ \ \ \ |multiply\ by\ 12\\\\ 12x+x=1248\\\\ 13x=1248\\\\x=96\\\\ Dog\ weights\ 96\ pounds.\)
Answer-
The weight of his dog is 96 pounds.
Solution-
Let's assume, weight of the Dylan's pet rabbit = x pounds, so weight of the Dylan's dog = 12x pounds,
The dog and rabbit weigh 104 pounds altogether, so
\(\Rightarrow x+12x=104\)
\(\Rightarrow 13x=104\)
\(\Rightarrow x=\dfrac{104}{13}\)
\(\Rightarrow x=8\)
So, the weight of rabbit is 8 pounds, and the weight of his dog is 8×12 = 96 pounds.