we know that
In a Rhombus all sides are congruent
so
AB=BC=CD=AD
Find the distance AB
\(A( 1,1)\\B(-2,-3)\)
The distance formula between two points is equal to
\(d=\sqrt{(y2-y1)^{2} + (x2-x1)^{2}}\)
\(d=\sqrt{(-3-1)^{2} + (-2-1)^{2}}\)
\(d=\sqrt{(-4)^{2} + (-3)^{2}}\)
\(d=\sqrt{25}=5\ units\)
Find the perimeter of a Rhombus
the perimeter of a rhombus is equal to
\(P=4d\)
where d is the length side of the rhombus
in this problem
\(d=5\ units\)
so
\(P=4*5\)
\(P=20\ units\)
therefore
the answer is
The perimeter of the rhombus is equal to \(20\ units\)
