If s(x) = 2 – x2 and t(x) = 3x, which value is equivalent to (sxt)(-7)?
(s o t)(-7) = s(t(-7)) = s(3(-7)) = s(-21) = 2 - (-21)^2 = 2 - 441 = -439
Step-by-step explanation:
\(s(x)= 2-x^2\)
\(t(x)= 3x\)
To find \((sot)(-7)= s(t(-7))\)
First we find t(-7) and then we plug it in s(x)
\(t(x)= 3x\), plug in -7 for x
\(t(-7)= 3(-7)=-21\)
\((sot)(-7)= s(t(-7))=s(-21)\), plug in -21 for x in s(x)
\(s(-21)= 2-(-21)^=-439\)
\((sot)(-7)= s(t(-7))=-439\)
If we are given with (s times t)(-7) we multiply it
\((s \cdot t)(-7)= s(-7) \cdot t(-7)\)
t(-7) is -21
\(s(-7)= 2-(-7)^2= -47\)
\((s \cdot t)(-7)= s(-7) \cdot t(-7)=-21 \cdot (-47)=987\)