write an equation in point-slope form of the line having the given slope that contains the given point. m=−0.8, (14.5,12.8) select one: a. y−14.5=−0.8(x−12.8) b. y−12.8=−0.8(x−14.5) c. y=−0.8x−1.2 d. y 12.8=−0.8(x−14.5)
y - y₁ = m(x -x₁)
slope m = -0.8, from point (14.5, 12.8) , x₁ = 14.5, y₁ = 12.8
y - y₁ = m(x -x₁)
y - 12.8 = -0.8(x - 14.5)
Option B
Answer: b. \((y-12.8)=-0.8(x-14.5)\)
Step-by-step explanation:
We know that the equation of a line in point slope form with slope m and passing through point (a,b) is given by :-
\((y-b)=m(x-a)\)
Given : The slope of the line : m= -0.8
The point from which line is passing : (a,b) =(14.5,12.8)
Then , the equation in point slope form of the line having the given slope that contains the given point. m=−0.8, (14.5,12.8) :-
\((y-12.8)=-0.8(x-14.5)\)