If quadratic function \(y=ax^2+bx+c\) has vertex that is the same as its y-intercept, then
\(x_v=-\dfrac{b}{2a}=0,\\ \\b=0\)
and its equation is \(y=ax^2+c.\)
The graph of this quadratic function is translated graph of the function \(y=ax^2\) up or down (depends on c).
This means that there could be
- two x-intercepts;
- one x-intercept;
- no x-intercepts.
The axis of symmetry of the graph of the function \(y=ax^2\) is x=0 (y-axis).
Answer: correct choice is A
