we have
\(f(x)=x^{2}-48\)
To find the roots equate the function to zero
\(x^{2}-48=0\)
Step 1
Adds \(48\) to both sides of the equation
\(x^{2}-48+48=0+48\)
\(x^{2}=48\)
Step 2
Take the square root of both sides
\(\sqrt{x^{2}}= \sqrt{48}\)
\(x=(+/-)\sqrt{48} \\x1=+\sqrt{48}=4\sqrt{3} \\ x2=-\sqrt{48}=-4\sqrt{3}\)
therefore
the answer is
The roots are
\(x1=4\sqrt{3}\)
\(x2=-4\sqrt{3}\)
