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ulapakulska
ulapakulska ulapakulska
  • 03-07-2016
  • Mathematics
Answered

Consider the curve y=ln(3x-1) Let P be the point on the curve where x = 2.

AWrite down the gradient of the curve at P.

(the anser is 0.6 but idk how they got there)

Verified Answer :

NiedzielnyMatematyk NiedzielnyMatematyk
  • 03-07-2016

\(y = \ln(3x-1) \\ \frac{\mathrm{d}y}{\mathrm{d}x} = \frac{1}{3x-1}\cdot 3 = \frac{3}{3x-1}\)

\(x=2\), so the gradient of this curve at \(P\) is \(\frac{3}{3\cdot 2-1} = \frac{3}{6-1} = \frac{3}{5} = 0.6\).

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