Answer:
A soccer stadium has 25 sections of seating.
Each section has 44 rows of seats, with 22 on the first row, 23 in the second row, 24 in the third row and so on.
A:
How many seats are there in row 44?
Arithmetic sequence is defined by
\(a_n= a1 +d(n- 1)\)
The common difference of the number of seats in each row is 1.
The first section has 22 seats.
Therefore,
\(a_n =22+(n -1)\)
\(a_n = n+21\)
So, \(a_44 = 44+21\)
= 65 seats
B:
How many seats are there in each section?
We can add up these as the number of seats in one section = a1 + a2 + a3 + a4 +...... + a44
\(Sum(44)= \frac{n}{2} (a+l)\)
= \(\frac{44}{2} (22+65)\)
= 1914 seats
C:
How many seats are there in the whole stadium?
As there are 25 sections and each section as 1914 seats so, the whole stadium has \(25\times1914=47850\) seats
= 47850 seats
