3r(2p-5)-p(2p-5) factorise it
3r(2p - 5) - p(2p - 5)The common factor is (2p - 5), therefore we can write:(2p - 5)(3r - p)
3r(2p - 5) - p(2p - 5)let a = 2p - 53r(2p - 5) - p(2p - 5) = 3ra - pa = a(3r - p)let's substitute back the value of a.a(3r - p) = (2p - 5)(3r - p)Therefore: 3r(2p - 5) - p(2p - 5) = (2p - 5)(3r - p)
