Line II
2x+3y=-5
3y=-2x-5
y=\(\frac{-2}{3} x- \frac{5}{3}\)
Gradient m= \(\frac{-2}{3}\)
Gradient of line I will be;
\(\frac{-2}{3} *m=-1\)
m=\(\frac{3}{2}\)
Equation of line I;
y=mx+c
y=\(\frac{3}{2} x+c\)
Finding value of c by replacing for;
y=1
x=-6
1=\(\frac{3}{2} *(-6)+c\)
c=10
y=\(\frac{3}{2} x+10\)
