a kite has vertices at (2, 4), (5, 4), (5, 1), and (0, –1). what is the approximate perimeter of the kite? round to the nearest tenth. 11.3 units 13.6 units 16.8 units 20.0 units
Perimeter = sum of length of sides = 2( sum of the unequal sides)
length of (2, 4) to (5, 4) = \(\sqrt{ (2-5)^{2} } = \sqrt{ (-3)^{2} } = \sqrt{9} =3 units\)
length of (5, 1) to (0, -1) =\(\sqrt{ (5-0)^{2}+(1+1)^2 } = \sqrt{ (5)^{2}+2^2 } = \sqrt{25+4} =\sqrt{29}=5.39 units\)
Perimeter = 2(3 + 5.39) = 2 x 8.39 = 16.8 units
The Perimeter of the Kite, rounded to the nearest tenth = 16.8 units
Perimeter = the sum of al the four sides of the kite.
Given:
Perimeter of kite = AB + BC + CD + DA
Applying the distance formula, \(d = \sqrt{(y_2 - y_1)^2 + (x_2 - x_1)^2}\), we have the following:
AB = √(5−2)² + (4−4)²
AB = √9
AB = 3 units
BC = √(5−5)² + (4−1)²
BC = √9
BC = 3 units
CD = √(0−5)² + (−1−1)²
CD = √29
CD = 5.39 units
DA = √(0−2)² + (−1−4)²
DA = √29
DA = 5.39 units
Thus:
Perimeter of the Kite = 5.39 + 5.39 + 3 + 3
Perimeter of the Kite = 16.8 units
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