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A gas has an initial volume of 168 cm3 at a temperature of 255 K and a pressure of 1.6 atm. The pressure of the gas decreases to 1.3 atm, and the temperature of the gas increases to 285 K.

Verified Answer :

olemakpadu

Would presume you are asked to find the volume, since there is no second volume.

By General Gas Law:

P₁V₁/T₁ = P₂V₂/T₂

1.6 168 /255 = 1.3V₂/285

V₂ = 1.6 168 285 / (1.3*255)

V₂ = 231.095

Final volume ≈ 231 cm³

Answer: The final volume is  \(231cm^3\)

Explanation: Using ideal gas equation:

\(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\)

\(P_1\)= initial pressure = 1.6 atm

\(V_1\)= initial volume = \(168cm^3\)

\(T_1\)= initial temperature = 255 K

\(P_2\)= final pressure= 1.3 atm

\(V_2\)= final volume = ?

\(T_2\)= final temperature = 285 K

\(\frac{1.6\times 168}{255}=\frac{1.3\times V_2}{285}\)

\(V_2=231cm^3\)


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