Answer: 0.8413
Step-by-step explanation:
Given : The average score on a standardized test is \(\mu=\text{750 points }\)
Standard deviation : \(\sigma=50\text{ points}\)
Let x be the score of randomly selected student.
The z-score for standardized test :-
\(z=\dfrac{x-\mu}{\sigma}\)
For x= 700
\(z=\dfrac{700-750}{50}=-1\)
The p-value = \(P(x>700)=P(z>-1)\)
\(1-P(z<1)=1-0.1586553=0.8413447\approx0.8413\)
Therefore, the probability that a student scores more than 700 on the standardized test = 0.8413
