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Determine the potential difference between two charged parallel plates that are 0.10 cm apart and have an electric field strength of 12 V/cm. V

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Formula for Electric Field strength , E =  V/d

where V = Voltage in volts, and d = distance of separation in meters.

d = 0.1 cm ,    E = 12 V/cm

E = V/d =  15 / 0.025

V = Ed

V = 12 0.1 = 1.2

Potential difference, V = 1.2 V 

Answer:

1.2 V

Explanation:

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