what is the value of the discriminant of the quadratic equation −2x2 = −8x 8, and what does its value mean about the number of real number solutions the equation has?
\(2x^2-8x+8=0 \\ d= b^{2} -4ac \\ =(-8)^2-4 \times 2 \times 8 \\ =64-64 \\ =0\) Since the discriminant is 0, the equation has one real number solution.
