we have
\(x^{2}-40=0\)
Step 1
Adds \(40\) to both sides of the equation
\(x^{2}-40+40=0+40\)
\(x^{2}=40\)
Step 2
Take the square root of both sides
\(\sqrt{x^{2}}= \sqrt{40}\)
\(x=(+/-)\sqrt{40} \\x1=+\sqrt{40}=2\sqrt{10} \\ x2=-\sqrt{40}=-2\sqrt{10}\)
therefore
the answer is
the first step in solving the quadratic equation is
Adds \(40\) to both sides of the equation
