Verified Answer :

meerkat18

The given expression, 81a^6 - 100, is a difference of two squares. The first term 81a^6 is a square of 9a³. The second term, 100, is a square of 10. The factors of the given expression is therefore, (9a³ - 10) x (9a³ + 10).

JeanaShupp

Answer:The factorization of \(81a^6-100=(9a^3+10)(9a^3-10)\)


Step-by-step explanation:

Given algebraic expression:\(81a^6-100\)

This can be written in the form of square as \((9a^3)^2-10^2\)

By using identity, \(a^2-b^2=(a+b)(a-b)\) , the above polynomial can be rewritten as

\((9a^3)^2-10^2=(9a^3+10)(9a^3-10)\)

Therefore the factorization of \(81a^6-100=(9a^3+10)(9a^3-10)\)


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