What is the inverse of y = 2x^2 – 8?
\(y = 2x^2 - 8 \\ 2x^2 = y + 8 \\ x^2 = \frac{y+8}{2} \\ x = \sqrt{\frac{y+8}{2}} \\ f^{-1} (x)=\sqrt{\frac{x+8}{2}}\)
