Answer:
\((9 \times 10^{-3})^2\) can be written in scientific notation as \(8.1 \times 10^{-5}\)
Step-by-step explanation:
A number is written in scientific notation if it can be written as \(p \times 10^x\) where p has value greater than or equal to 1 and less than 10 and x is an integer.
Given - \((9 \times 10^{-3})^2\)
First applying \((ab)^2=a^2b^2\)
We get, \((9 \times 10^{-3})^2=9^2 \times (10^{-3})^2\)
using property of exponents \((a^n)^m=a^{nm}\)
\(9^2 \times (10^{-3})^2=81 times 10^{-6}\)
Thus, we have to write \(81 times 10^{-6}\) in scientific notation,
Multiply and divide by 10 , we get
\(81 times 10^{-6}=8.1 \times 10^{-5}\)
Thus, \((9 \times 10^{-3})^2\) can be written in scientific notation as \(8.1 \times 10^{-5}\)
