Answer:
The solution sets is all real numbers in case of:
|x| > -1
Step-by-step explanation:
We know that modulus is a function with the property such that:
if a<0 then |a|= -a
that is the modulus of a negative number is positive and if a≥0
then |a| =a
and modulus of a positive value is also positive.
i.e. modulus function always gives positive value.
Hence,
1)
|x|<-1
This is not possible as modulus function always gives a value ≥0 for all real numbers.
2)
|x|= -1
This is also not possible as modulus of any number can't be negative.
3)
|x| > -1
The modulus of any number will definitely be greater than or equal to zero.
Hence, the solution set contain all the real numbers.
