Answer : The energy of a photon is, \(4.073\times 10^{-19}J\)
Explanation :
Formula used :
\(E=\frac{h\times c}{\lambda}\)
where,
E = energy = ?
h = Planck's constant = \(6.626\times 10^{-34}Js\)
c = speed of light = \(3\times 10^8m/s\)
\(\lambda\) = wavelength = \(488\times 10^{-9}m\)
Now put all the given values in the above formula, we get the energy.
\(E=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{488\times 10^{-9}m}\)
\(E=4.073\times 10^{-19}J\)
Therefore, the energy of a photon is, \(4.073\times 10^{-19}J\)
