The slope-intercept form of the equation of a line that passes through point (–2, –13) is y = 5x – 3. What is the point-slope form of the equation for this line?

y – 13 = 5(x – 2)

y + 13 = 5(x + 2)

y – 2 = 5(x – 13)

y + 2 = 5(x + 13)

Verified Answer :

we know that

the point-slope form of the equation of the line is

\(y-y1=m(x-x1)\)

in this problem we have

\(m=5\) ----> given line

\((x1,y1)=(-2,-13)\)

substitute in the equation of the line

\(y-(-13)=5(x-(-2))\)  

\(y+13=5(x+2)\)  

therefore

the answer is the option

\(y+13=5(x+2)\)  

Answer:

B

Step-by-step explanation:

Its B!

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