The Resultant Speed of boat rowed at 8km/hr directly across a river that flows at 6km/hr is 10km/hr
Given the data in the question;
Velocity of boat; \(V_m = 8km/hr\)
Velocity of the flowing river; \(V_r = 6km/hr\)
Resultant Velocity; \(V = ?\)
Now, as illustrated in the diagram below, a right angled triangle is formed.
Now, to get the V, which is the resultant velocity or speed, we make use of the Pythagorean theorem:
\(c^2 = a^2 + b^2\)
In our case,
\(V^2 = V_r^2 + V_m^2\)
We find the square root of both sides
\(V = \sqrt{V_r^2 + V_m^2}\)
Now, we substitute in our given values
\(V = \sqrt{(6km/hr)^2 + (8km/hr)^2}\\\\V = \sqrt{ (36km^2/hr^2) + ( 64 km^2/hr^2)\\\)
\(V = \sqrt{100 km^2/hr^2\)
\(V = 10km/hr\)
Therefore, The Resultant Speed of boat rowed at 8km/hr directly across a river that flows at 6km/hr is 10km/hr
Learn more; https://brainly.com/question/11737468
