Verified Answer :

nobillionaireNobley

For a
0 > -3(1) + 3 i.e. 0 > 0 (not true)
For b
1 > -3(-1) + 3 i.e. 1 > 6 (not true)
For c
2 > -3(2) + 3 i.e. 2 > -3 (true)
2 > 2(2) - 2 i.e. 2 > 2 (not true)
For d
3 > -3(0) + 3 i.e. 3 > 3 (not true)

Therefore, none of the ordered pairs makes both inequalities correct.

david8644

Answer:

a. (1,0)

Step-by-step explanation:

In order to calculate this, you just have ot insert the value of X into the inequality to evaluate it and see if it makes both correct, remember that the points are ordered as (x,y).

First enequality:

\(y=-3x+3\\y=-3(x)+3\\y=0\)

SO we know that the first one is true, the second one would be:

\(y=2x-2\\y=2(1)-2\\y=0\\\)

Now we know that both inequalities are true when evaluated for (1,0)

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