hjmilleman hjmilleman

29-06-2016
Chemistry

Answered

A solution has a pH of 2.5. What is its [OH-] ?

Verified Answer :

29-06-2016

pOH=14-pH=14-2.5=11.5
pH=-log[H+]
2.5=-log [H+]
[H+]=10^-5/2
[OH-]=10^(14-5/2)=10^23/2

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