Given EG = 16 and FH = 12, what is the length of one side of the rhombus? 6 units 8 units 10 units 14 units PLEASE HELP ONLY COMMENT IF YOU KNOW THE ANSWER
EG and FH are diagonals of the rhombus and the bisect each other at the centre to for a righ angle triangle with the side of the rhombus as the hypothenus.
By pythagoras theorem, \(length = \sqrt{ 8^{2} + 6^{2} } = \sqrt{64+36} = \sqrt{100} =10 \ units\)