Answer:
\((-5,-1)\)
Step-by-step explanation:
We are asked to find the vertex of the function \(y=x^2+10x+24\).
First of all, we will find x-coordinate of vertex using formula \(\frac{-b}{2a}\).
\(\frac{-10}{2*1}\)
\(\frac{-10}{2}\)
\(-5\)
Now, we will substitute \(x=-5\) in our given formula to find y-coordinate of vertex as:
\(y=(-5)^2+10(-5)+24\)
\(y=25-50+24\)
\(y=-50+49\)
\(y=-1\)
Therefore, point \((-5,-1)\) is the vertex of the given function.
