The intersections be x-intercept(s): (36,0) and
y-intercept(s): (0,9)
How to estimate x- and y- intercept of the line?
Let, \(x + 4y = 36\)
To find the x-intercept(s), substitute in 0 for y and solve for x.
\(x + 4(0) = 36\)
Simplify x + 4(0).
Multiply 4 by 0.
x + 0 = 36
Add x and 0.
\(x = 36\)
x-intercept(s) in point form.
x-intercept(s): (36,0)
To find the y-intercept(s), substitute in 0 for x and solve for y.
\((0)+4 y=36\)
Solving the above equation, we get
Add 0 and 4y.
\($4y = 36\)
Divide each term by 4 and simplify.
Divide each term in 4y = 36 by 4.
\($\frac{4 y}{4}=\frac{36}{4}$\)
Cancel the common factor of 4.
Cancel the common factor.
\($\frac{4 y}{4}=\frac{36}{4}$\)
Divide y by 1.
\($y=\frac{36}{4}\)
Divide 36 by 4.
\(y = 9\)
y-intercept(s) in point form.
y-intercept(s): (0,9)
Therefore, the intersections be x-intercept(s): (36,0) and
y-intercept(s): (0,9).
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