Answered

Complete the square to solve the equation below


x^2+x=7/4

Ax=-2+√2 ; x=-2 - √2
Bx=-1/2+√2 ; x=-1/2- √2
Cx=3 ; x=-1
Dx=1+√2 ; x=1- √2

Verified Answer :

xSamx

\(x^2+x= \frac{7}{4}\)

Take one-half of the coefficient of x and square it, then add it to both sides.

\(x^2+x+ (\frac{1}{4}) =\frac{7}{4}+ (\frac{1}{4})\)

\(x^2+x+(\frac{1}{4})= 2\)

\(\left(x+\frac{1}{2}\right)^2=2\)

\(x+\frac{1}{2}=\pm \sqrt{2}\)
-----------------------------------------------------------------
\(x+\frac{1}{2}=- \sqrt{2}\)
\(x=-\frac{1}{2}- \sqrt{2}\) <=

AND

\(x+\frac{1}{2}= \sqrt{2}\)
\(x= \sqrt{2}-\frac{1}{2}\) <=

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