Answer:
The solution is the option C
\((3,-1)\)
Step-by-step explanation:
we have
\(2x+3y=3\) -----> equation A
\(7x-3y=24\) -----> equation B
Adds equation A and equation B
\(2x+3y=3\\7x-3y=24\\---------\\2x+7x=3+24\\9x=27\\x=3\)
Find the value of y
\(2(3)+3y=3\)
\(6+3y=3\)
Subtract \(6\) both sides
\(3y=3-6\)
\(3y=-3\)
Divide by \(3\) both sides
\(y=-1\)
The solution is the point \((3,-1)\)
