Verified Answer :

\(243^{ \frac{2}{5} } = ( \sqrt[5]{243} )^{2} = 3^{2} =9\)

ANSWER

\({(243)}^{ \frac{2}{5} } = 9\)


EXPLANATION

We want to simplify the exponential expression,


\({(243)}^{ \frac{2}{5} }\)


We use the laws of indices to simplify the expression.



We rewrite the above expression to obtain,

\({(243)}^{ \frac{2}{5} } = {(243)}^{ \frac{1}{5} \times 2 }\)

Recall that,


\({a}^{mn} = ( {a}^{m} ) ^{n}\)


When we apply the above property, we get

\({(243)}^{ \frac{2}{5} } = {( {(243)}^{ \frac{1}{5} } )}^{2}\)


Now we need to write
\(243\)
as a certain number to the exponent of 5.



In order words,

\(243 = 3 \times 3 \times 3 \times 3 \times 3 = {3}^{5}\)



This implies that,


\({(243)}^{ \frac{2}{5} } = {( { {3}^{5} }^{ \times \frac{1}{5} } )}^{2}\)



We further simplify to get,


\({(243)}^{ \frac{2}{5} } = 3^{2}\)


This will finally evaluate to,


\({(243)}^{ \frac{2}{5} } = 9\)