what is the resistance of a 12m long wire having radius( 210 to the power - 4) and resistivity (3.1410 to the power - 8)ohmM

Verified Answer :

R = ρl/A

Where R = Resistance in Ohms, Ω, ρ = Resistivity in Ωm, l = Length in m.

Area in m²

ρ = Resistivity = 3.14 10⁻⁸ Ωm,  Length l = 12m, 

Area = πr² = π
(210⁻⁴)² m² ≈ 3.14 (210⁻⁴)² m²


R = ρl/A

    ≈ 3.14
10⁻⁸ 12 / (3.14 (2*10⁻⁴)²)

     ≈ 3

Resistance, R ≈ 3 Ω