Lindsie wants to see how many times she needs to roll a standard number cube before getting a 1. What is the probability Lindsie will roll a 1 on her fifth roll and not before?

5/6 x 5/6 x 5/6 x 5/6 x 1/6

625/7776

This is the probability of her rolling a 1 on her fifth roll and not before.

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chisnau chisnau · Answer 2 · 2019-05-15T15:48:10-04:00

Answer:

The answer is : \(\frac{125}{7776}\)

Step-by-step explanation:

A standard number cube has numbers from 1 to 6 on it.

Here, given is that Lindsie wants to see how many times she needs to roll a standard number cube before getting a 1.

p = \(\frac{1}{6}\) (on an average: roll 6 times before getting a 1)

The probability that Lindsie will roll a 1 on her fifth roll and not before is :

P= 1\(\frac{1}{5}(\frac{5}{6}*\frac{5}{6}*\frac{5}{6}*\frac{5}{6}*\frac{1}{6})\)

= \(\frac{625}{38880}\)

Simplifying it we get,

Divide by 5:

\(\frac{125}{7776}\)