Which ordered pairs make both inequalities true? Check all that apply.


y < 5x + 2


y >= 1/2x + 1


These are the choices....

#1. (–3, 2)


#2. (–1, 3)


#3. (0, 2)


#4. (1, 2)

#5. (2, –1)

#6. (2, 2)

Verified Answer :

All others did not satisfy the inequality simultaneously except #4 and #6
For #4:
2 < 5(1) + 2 i.e. 2 < 7 (true)
2 >= 1/2(1) + 1 i.e. 2 >= 3/2  (true)
For #6
2 < 5(2) + 2 i.e. 2 < 12 (true)
2 >= 1/2(2) + 1 i.e. 2 >= 2

we have

\(y < 5x + 2\) -------> inequality \(1\)\(y \geq \frac{1}{2}x + 1\) -------> inequality \(2\)

using a graph tool

see the the attached figure N \(1\)

the solution of the system is the shaded area

\(case 1) (-3, 2)\)

This point satisfies the inequality \(2\) but does not satisfy the inequality \(1\).

therefore

it is not a solution of the system

see the attached figure N \(2\)


inequality \(1\)

\((-3,2)\\ x=-3\\ y=2\)

\(2 < 5*(-3) + 2\)

\(2 < -13\) -----> is not true

inequality \(2\)

\((-3,2)\\ x=-3\\ y=2\)

\(2 \geq \frac{1}{2}*(-3) + 1\)

\(2 \geq -\frac{1}{2}\) -----> is true

\(case 2) (-1, 3)\)

This point satisfies the inequality \(2\) but does not satisfy the inequality \(1\).

therefore

it is not a solution of the system

see the attached figure N \(2\)


inequality \(1\)

\((-1, 3)\\ x=-1\\ y=3\)

\(3 < 5*(-1) + 2\)

\(3 < -3\) -----> is not true

inequality \(2\)

\((-1, 3)\\ x=-1\\ y=3\)

\(3 \geq \frac{1}{2}*(-1) + 1\)

\(3 \geq \frac{1}{2}\) -----> is true

\(case 3) (0, 2)\)

This point satisfies the inequality \(2\) but does not satisfy the inequality \(1\).

therefore

it is not a solution of the system

see the attached figure N \(2\)


inequality \(1\)

\((0, 2)\\ x=0\\ y=2\)

\(2 < 5*(0) + 2\)

\(2 < 2\) -----> is not true

inequality \(2\)

\((0, 2)\\ x=0\\ y=2\)

\(2 \geq \frac{1}{2}*(0) + 1\)

\(2 \geq 1\) -----> is true

\(case 4) (1, 2)\)

This point satisfies the inequality \(2\) and satisfies the inequality \(1\).

therefore

it is a solution of the system

see the attached figure N \(2\)


inequality \(1\)

\((1, 2)\\ x=1\\ y=2\)

\(2 < 5*(1) + 2\)

\(2 < 7\) -----> is true

inequality \(2\)

\((1, 2)\\ x=1\\ y=2\)

\(2 \geq \frac{1}{2}*(1) + 1\)

\(2 \geq \frac{3}{2}\) -----> is true

\(case 5) (2,-1)\)

This point satisfies the inequality \(1\) but does not satisfy the inequality \(2\).

therefore

it not a solution of the system

see the attached figure N \(2\)


inequality \(1\)

\((2, -1)\\ x=2\\ y=-1\)

\(-1 < 5*(2) + 2\)

\(-1 < 12\) -----> is true

inequality \(2\)

\((2, -1)\\ x=2\\ y=-1\)

\(-1 \geq \frac{1}{2}*(2) + 1\)

\(-1 \geq 2\) -----> is not true

\(case 6) (2, 2)\)

This point satisfies the inequality \(1\) and satisfies the inequality \(2\).

therefore

it is a solution of the system

see the attached figure N \(2\)


inequality \(1\)

\((2, 2)\\ x=2\\ y=2\)

\(2 < 5*(2) + 2\)

\(2 < 12\) -----> is true

inequality \(2\)

\((2, 2)\\ x=2\\ y=2\)

\(2 \geq \frac{1}{2}*(2) + 1\)

\(2 \geq 2\) -----> is true

therefore

the answer is

\(case 4) (1, 2)\\ case 6) (2, 2)\)

View image calculista
View image calculista